-(3x-2)(x^2-3x+1)=0

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Solution for -(3x-2)(x^2-3x+1)=0 equation: 


Simplifying
-1(3x + -2)(x2 + -3x + 1) = 0

Reorder the terms:
-1(-2 + 3x)(x2 + -3x + 1) = 0

Reorder the terms:
-1(-2 + 3x)(1 + -3x + x2) = 0

Multiply (-2 + 3x) * (1 + -3x + x2)
-1(-2(1 + -3x + x2) + 3x * (1 + -3x + x2)) = 0
-1((1 * -2 + -3x * -2 + x2 * -2) + 3x * (1 + -3x + x2)) = 0
-1((-2 + 6x + -2x2) + 3x * (1 + -3x + x2)) = 0
-1(-2 + 6x + -2x2 + (1 * 3x + -3x * 3x + x2 * 3x)) = 0
-1(-2 + 6x + -2x2 + (3x + -9x2 + 3x3)) = 0

Reorder the terms:
-1(-2 + 6x + 3x + -2x2 + -9x2 + 3x3) = 0

Combine like terms: 6x + 3x = 9x
-1(-2 + 9x + -2x2 + -9x2 + 3x3) = 0

Combine like terms: -2x2 + -9x2 = -11x2
-1(-2 + 9x + -11x2 + 3x3) = 0
(-2 * -1 + 9x * -1 + -11x2 * -1 + 3x3 * -1) = 0
(2 + -9x + 11x2 + -3x3) = 0

Solving
2 + -9x + 11x2 + -3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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